
Quarter Circles
Problem
Four quarter circles are drawn from each vertex in a unit square.

Find the area of the shaded region.
Solution
Consider the diagram below.

By using the unit circle (see diagram below), we can find the area between 0.5 and a by integrating under the curve, x² + y2 = 1.
That is, y =
(1
x2); taking positive root, because we only want the top part of the circle.

Using the Pythagorean Theorem, 12 = a2 + ½2
a =
3/2.
| Area under curve = |
|
Using the substitution, x = sin(u), dx = cos(u) du, and we get:
| Area under curve | = |
| cos2(u) du | |||
| = |
| ½(1 |
| = | ½[u + ½cos(2u)] |
| = | π/12 | ||||
Area of rectangle = ½(
3/2
1/2) = (
3
1)/4.
Area of ¼ shaded region = π/12
(
3
1)/4.
Hence the area of the shaded region is, π/3
3 + 1.
Problem ID: 142 (Dec 2003) Difficulty: 4 Star
RSS
Show Solution
Hide Solution