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Two-digit Sum And Product

Problem

If you multiply together the digits of the number 42, 4 times 2 = 8, but if you add the digits together, 4 + 2 = 6. For the number 31, the product of the digits, 3 times 1 = 3 and the sum of the digits, 3 + 1 = 4.

Can you find a two-digit number for which the product of its digits is the same as the sum of its digits?


Solution

Given the 2-digit number. (ab), we are solving: a + b = ab.

Therefore ab minus b = a, b(a minus 1) = a, giving b = a/(a minus 1).

Considering the possible values of the digit, a: b = 2/1, 3/2, 4/3, ..., 9/8 and the only integer solution is 2/1; that is, a = 2 and b = 2.

Hence there is only one two-digit solution, 22.

For which 2-digit numbers do the product of their digits exceed their sum?
Can you find any 3-digit number for which the sum of the digits is equal to the product of its digits?
What about n-digit numbers?

Problem ID: 118 (May 2003)     Difficulty: 1 Star

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