mathschallenge.net logo

Almost Equilateral Triangles

Problem

We shall define an $almost equilateral triangles$ to be a triangle for which two sides are equal and the third differs by no more than one unit. The smallest such triangle with integral length sides and area is 5-5-6.

Prove that infintitely many $almost equilateral triangles$ with integral length sides and area exist.

Solution

By the definition an $almost equilateral triangles$ measuring $a-a-b$ is isosceles.


Using the Pythagorean Theorem: $a$2 = ($b$/2)2 + $h$2, so 4$a$2 = $b$2 + 4$h$2.

As $b$ = $a$ plus or minus 1, $b$2 = $a$2 plus or minus 2$a$ + 1

therefore 4$a$2 = $a$2 plus or minus 2$a$ + 1 + 4$h$2
    3$a$2 plus or minus 2$a$ minus 1 + 4$h$2 = 0
    9$a$2 plus or minus 6$a$ minus 3 minus 12$h$2 = 0
    9$a$2 plus or minus 6$a$ + 1 minus 12$h$2 = 4
    (3$a$ plus or minus 1)2 minus 12$h$2 = 4
therefore ((3$a$ plus or minus 1)/2)2 minus 3$h$2 = 1

By writing $x$ = (3$a$ plus or minus 1)/2 and $y$ = $h$, we get the Pell equation: $x$2 minus 3$y$2 = 1. Given one solution, it is well known that Pell equations have infinitely many solutions, and for completeness we shall prove this.

However, we must first show that integer $x$ corresponds to an integer solutions for $a$; $b$ being integer follows as $b$ = $a$ plus or minus 1.

As $x$ = (3$a$ plus or minus 1)/2, we get $a$ = (2$x$plus or minus1)/3

It should be clear that $x$ cannot be divisible by 3, otherwise $x$2 minus 3$y$2 would be a multiple of 3 and could not be equal to 1.

So given that $x$ congruent plus or minus1 mod 3, 2$x$ congruent plus or minus 1 mod 3, and so one of 2$x$+1 or 2$x$minus1 will be a multiple of 3. Hence for every integer solution of the equation $x$2 minus 3$y$2 = 1, we have an integer solution for $a$ and $b$. Now we shall prove that infinitely many solutions exist.

Given ($x$,$y$), a solution pair to the Pell equation $x$2 minus 3$y$2 = 1, consider the larger pair ($x$2+3$y$2,2$xy$):

($x$2+3$y$2)2 minus 3(2$xy$)2 = $x$4 + 6$x$2$y$2 + 9$y$4 minus 12$x$2$y$2
  = $x$4 minus 6$x$2$y$2 + 9$y$4
  = ($x$2 minus 3$y$2)2
  = 1

In other words, if ($x$,$y$) is a solution then ($x$2+3$y$2,2$xy$) will also be a solution, and as (7,4) leads to the first solution 5-5-6, we prove that infinitely many $almost equilateral triangles$ with integral length sides and area exist.

Note that although the infinite solution set of the Pell equation $x$2 minus 3$y$2 = 1 is in a one-to-one mapping with the set of $almost equilateral triangles$ we are seeking, this particular iterative method: ($x$,$y$) maps ($x$2+3$y$2,2$xy$), will NOT produce every solution.

Problem ID: 219 (30 Mar 2005)     Difficulty: 4 Star

Only Show Problem